1. The problem is to analyze the function $f(x) = 2x - 1$. 2. This is a linear function of the form $f(x) = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 3. The slope $m = 2$ means the function increases by 2 units vertically for every 1 unit increase horizontally. 4. The y-intercept $b = -1$ means the graph crosses the y-axis at the point $(0, -1)$. 5. To find the x-intercept, set $f(x) = 0$ and solve for $x$: $$0 = 2x - 1$$ $$2x = 1$$ $$x = \frac{1}{2}$$ So the x-intercept is at $(\frac{1}{2}, 0)$. 6. Since this is a linear function, it has no extrema (no maximum or minimum points). 7. Summary: - Slope: 2 - Y-intercept: $(0, -1)$ - X-intercept: $(\frac{1}{2}, 0)$ - No extrema Final answer: The function $f(x) = 2x - 1$ is a straight line with slope 2, y-intercept at $(0, -1)$, and x-intercept at $(\frac{1}{2}, 0)$.