Subjects algebra

Linear Equations Solve

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Search Solutions

Linear Equations Solve


1. Solve for $x$ in each equation: a. Given $\frac{x}{2} + 1 = 3$ Subtract 1 from both sides: $\frac{x}{2} = 2$ Multiply both sides by 2: $x = 4$ b. Given $\frac{x}{2} - 5 = 6$ Add 5 to both sides: $\frac{x}{2} = 11$ Multiply both sides by 2: $x = 22$ c. Given $\frac{x}{8} + 3 = 5$ Subtract 3 from both sides: $\frac{x}{8} = 2$ Multiply both sides by 8: $x = 16$ d. Given $-4 + \frac{x}{3} = -1$ Add 4 to both sides: $\frac{x}{3} = 3$ Multiply both sides by 3: $x = 9$ e. Given $\frac{x}{3} - 4 = -11$ Add 4 to both sides: $\frac{x}{3} = -7$ Multiply both sides by 3: $x = -21$ f. Given $2 + \frac{x}{6} = -2$ Subtract 2 from both sides: $\frac{x}{6} = -4$ Multiply both sides by 6: $x = -24$ g. Given $\frac{x}{9} - 7 = 0$ Add 7 to both sides: $\frac{x}{9} = 7$ Multiply both sides by 9: $x = 63$ h. Given $5 + \frac{x}{7} = -3$ Subtract 5 from both sides: $\frac{x}{7} = -8$ Multiply both sides by 7: $x = -56$ i. Given $\frac{x}{11} + 31 = 33$ Subtract 31 from both sides: $\frac{x}{11} = 2$ Multiply both sides by 11: $x = 22$ 2. Solve for $x$ in each equation: a. Given $\frac{x}{-3} + 2 = -1$ Subtract 2 from both sides: $\frac{x}{-3} = -3$ Multiply both sides by $-3$: $x = 9$ b. Given $\frac{x}{-2} - 3 = 0$ Add 3 to both sides: $\frac{x}{-2} = 3$ Multiply both sides by $-2$: $x = -6$ c. Given $-\frac{x}{2} - 5 = 1$ Add 5 to both sides: $-\frac{x}{2} = 6$ Multiply both sides by $-2$: $x = -12$ d. Given $3 - \frac{x}{2} = 5$ Subtract 3 from both sides: $-\frac{x}{2} = 2$ Multiply both sides by $-2$: $x = -4$ e. Given $5 - \frac{x}{5} = 1$ Subtract 5 from both sides: $-\frac{x}{5} = -4$ Multiply both sides by $-5$: $x = 20$ f. Given $6 - \frac{x}{3} = -2$ Subtract 6 from both sides: $-\frac{x}{3} = -8$ Multiply both sides by $-3$: $x = 24$