Linear Function
1. Problem: Find the equation of the line passing through points (1,2) and (3,6).
Step 1: Calculate the slope $m = \frac{6-2}{3-1} = \frac{4}{2} = 2$.
Step 2: Use point-slope form $y - y_1 = m(x - x_1)$ with point (1,2):
$$y - 2 = 2(x - 1)$$
Step 3: Simplify to slope-intercept form:
$$y = 2x - 2 + 2 = 2x$$
2. Problem: Find the line with slope -1 passing through (4,3).
Step 1: Point-slope form:
$$y - 3 = -1(x - 4)$$
Step 2: Simplify:
$$y = -x + 4 + 3 = -x + 7$$
3. Problem: Determine the equation of the line with y-intercept 5 and slope 0.5.
Step 1: Slope-intercept form:
$$y = 0.5x + 5$$
4. Problem: Find the equation of the horizontal line through (2, -3).
Step 1: Horizontal line means slope $m=0$, so:
$$y = -3$$
5. Problem: Find the equation of the vertical line through $x=7$.
Step 1: Vertical lines have undefined slope, equation:
$$x = 7$$
6. Problem: Find the equation of the line passing through (0,0) with slope 3.
Step 1: Slope-intercept form:
$$y = 3x$$
7. Problem: Equation of a line passing through (-1,-1) and (2,4).
Step 1: Compute the slope:
$$m = \frac{4 - (-1)}{2 - (-1)} = \frac{5}{3}$$
Step 2: Point-slope form using (-1,-1):
$$y + 1 = \frac{5}{3}(x + 1)$$
Step 3: Simplify:
$$y = \frac{5}{3}x + \frac{5}{3} - 1 = \frac{5}{3}x + \frac{2}{3}$$
8. Problem: Find the line with slope 4 that passes through (3,5).
Step 1: Point-slope form:
$$y - 5 = 4(x - 3)$$
Step 2: Simplify:
$$y = 4x - 12 + 5 = 4x - 7$$
9. Problem: Find slope and equation of the line passing through points (6,2) and (6,8).
Step 1: The vertical line has undefined slope.
Step 2: Equation:
$$x = 6$$
10. Problem: Find the equation of the line passing through (2, 3) with slope $
-2$.
Step 1: Point-slope form:
$$y - 3 = -2(x - 2)$$
Step 2: Simplify:
$$y = -2x + 4 + 3 = -2x + 7$$