1. The problem states that we have two lines: a vertical line at $x=3$ and a horizontal line at $y=-2$. 2. A vertical line at $x=3$ means all points on this line have an $x$-coordinate of 3. 3. A horizontal line at $y=-2$ means all points on this line have a $y$-coordinate of -2. 4. The intersection point of these two lines is where both conditions are true simultaneously. 5. Therefore, the intersection point is at $(3, -2)$. 6. This point satisfies both equations: $x=3$ and $y=-2$. Final answer: The intersection point is $(3, -2)$.