1. The problem is to find the correct graph for the linear equation $3x + 2y = 4$. 2. To graph a linear equation, we find the intercepts where the line crosses the axes. 3. Find the x-intercept by setting $y=0$: $$3x + 2(0) = 4 \implies 3x = 4 \implies x = \frac{4}{3}$$ So the x-intercept is $\left(\frac{4}{3}, 0\right)$. 4. Find the y-intercept by setting $x=0$: $$3(0) + 2y = 4 \implies 2y = 4 \implies y = 2$$ So the y-intercept is $(0, 2)$. 5. Plotting these points and drawing a straight line through them gives the graph of the equation. 6. The line crosses the x-axis at $\left(\frac{4}{3}, 0\right)$ and the y-axis at $(0, 2)$, matching the description. 7. The slope-intercept form can also be found by solving for $y$: $$2y = 4 - 3x \implies y = 2 - \frac{3}{2}x$$ This confirms the line has slope $-\frac{3}{2}$ and y-intercept $2$. Final answer: The graph is a straight line crossing the x-axis at $\left(\frac{4}{3}, 0\right)$ and the y-axis at $(0, 2)$, exactly as described.