1. The problem provides two equations: $X = -2y - 6$ and $X + 2y = -6$. We need to graph these equations. 2. First, rewrite both equations in terms of $X$ and $y$: - From the first equation: $X = -2y - 6$ - From the second equation: $X + 2y = -6 \Rightarrow X = -6 - 2y$ 3. Notice that both equations are actually the same: $X = -2y - 6$. 4. To graph this line, isolate $y$ in terms of $X$: $$X = -2y - 6 \Rightarrow -2y = X + 6 \Rightarrow y = -\frac{X + 6}{2} = -\frac{1}{2}X - 3$$ 5. This is a linear equation with slope $-1/2$ and $y$-intercept $-3$. 6. To find the $x$-intercept, set $y = 0$: $$0 = -\frac{1}{2}X - 3 \Rightarrow -\frac{1}{2}X = 3 \Rightarrow X = -6$$ 7. To find the $y$-intercept, set $X=0$: $$y = -\frac{1}{2} \times 0 - 3 = -3$$ 8. The line passes through points $(-6, 0)$ and $(0, -3)$. Final answer: The graph is a line with equation $$y = -\frac{1}{2}X - 3$$, passing through intercepts $(-6,0)$ and $(0,-3)$.