1. **Find the features of line A**. Line A passes through points (1,0) and (0,6). Gradient (slope) is calculated by: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 - 0}{0 - 1} = \frac{6}{-1} = -6$$ The x-intercept is where $y=0$. Given point (1,0), x-intercept is $1$. The y-intercept is where $x=0$. Given point (0,6), y-intercept is $6$. 2. **Find the features of line B**. Line B passes through points (0,-2) and (6,4). Gradient: $$m = \frac{4 - (-2)}{6 - 0} = \frac{6}{6} = 1$$ x-intercept: When $y=0$, find $x$ using the line equation. Equation in slope-intercept form: $$y = mx + c = 1\cdot x + (-2) = x - 2$$ Set $y=0$: $$0 = x - 2 \Rightarrow x = 2$$ y-intercept is $c = -2$. 3. **Find the intercepts of line given by** $$y - 8x = 24$$. Rewrite in slope-intercept form: $$y = 8x + 24$$ x-intercept (set $y=0$): $$0 = 8x + 24 \Rightarrow 8x = -24 \Rightarrow x = -3$$ y-intercept (set $x=0$): $$y = 8\times0 + 24 = 24$$ **Final Answers:** - Line A: Gradient = $-6$, x-intercept = $1$, y-intercept = $6$ - Line B: Gradient = $1$, x-intercept = $2$, y-intercept = $-2$ - Line $y - 8x = 24$: x-intercept = $-3$, y-intercept = $24$