Subjects algebra

Line Equation Fa6Bda

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Line Equation Fa6Bda


1. The problem is to find the equation of a line given a point and a slope. 2. The point-slope form of a line is given by the formula: $$y - y_1 = m(x - x_1)$$ where $m$ is the slope and $(x_1, y_1)$ is a point on the line. 3. Given the point $(8, 13.4)$ and slope $m = 0.2$, substitute these values into the formula: $$y - 13.4 = 0.2(x - 8)$$ 4. Distribute the slope on the right side: $$y - 13.4 = 0.2x - 1.6$$ 5. Add $13.4$ to both sides to solve for $y$: $$y = 0.2x - 1.6 + 13.4$$ 6. Simplify the right side: $$y = 0.2x + 11.8$$ 7. This is the slope-intercept form of the line, showing a line with slope $0.2$ passing through the point $(8, 13.4)$. Final answer: $$y = 0.2x + 11.8$$