Line Equation Fa10F7
1. **State the problem:** Find the equation of line N passing through points $(-2, -30)$ and $(0, 10)$ in the form $y = mx + c$.
2. **Formula used:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
The equation of the line is then
$$y = mx + c$$
where $c$ is the y-intercept.
3. **Calculate the slope:**
$$m = \frac{10 - (-30)}{0 - (-2)} = \frac{10 + 30}{0 + 2} = \frac{40}{2} = 20$$
4. **Find the y-intercept $c$:** Since the line passes through $(0, 10)$, the y-intercept is
$$c = 10$$
5. **Write the equation:**
$$y = 20x + 10$$
**Final answer:** The equation of line N is $y = 20x + 10$.