Subjects algebra

Line Equation Fa10F7

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Line Equation Fa10F7


1. **State the problem:** Find the equation of line N passing through points $(-2, -30)$ and $(0, 10)$ in the form $y = mx + c$. 2. **Formula used:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ The equation of the line is then $$y = mx + c$$ where $c$ is the y-intercept. 3. **Calculate the slope:** $$m = \frac{10 - (-30)}{0 - (-2)} = \frac{10 + 30}{0 + 2} = \frac{40}{2} = 20$$ 4. **Find the y-intercept $c$:** Since the line passes through $(0, 10)$, the y-intercept is $$c = 10$$ 5. **Write the equation:** $$y = 20x + 10$$ **Final answer:** The equation of line N is $y = 20x + 10$.