Line Equation E9B711
1. **State the problem:** Find the equation of the line passing through points $(3, -4)$ and $(-2, 6)$ in gradient-intercept form $y = mx + b$.
2. **Formula for slope:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
3. **Calculate the slope:**
$$m = \frac{6 - (-4)}{-2 - 3} = \frac{6 + 4}{-5} = \frac{10}{-5} = -2$$
4. **Use point-slope form:**
$$y - y_1 = m(x - x_1)$$
Using point $(3, -4)$:
$$y - (-4) = -2(x - 3)$$
$$y + 4 = -2x + 6$$
5. **Convert to gradient-intercept form:**
$$y = -2x + 6 - 4$$
$$y = -2x + 2$$
**Final answer:** The equation of the line is
$$y = -2x + 2$$