1. **State the problem:** Find the equation of the line passing through points $(0,3)$ and $(5,0)$ and write it in standard form. 2. **Find the slope $m$ using the formula:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 3}{5 - 0} = \frac{-3}{5}$$ 3. **Use point-slope form with point $(0,3)$:** $$y - y_1 = m(x - x_1)$$ $$y - 3 = -\frac{3}{5}(x - 0)$$ $$y = -\frac{3}{5}x + 3$$ 4. **Convert to standard form $Ax + By = C$:** Multiply both sides by 5 to clear the fraction: $$5y = -3x + 15$$ Rearranged: $$3x + 5y = 15$$ 5. **Interpretation:** The standard form equation of the line is $3x + 5y = 15$. **Final answer:** $3x + 5y = 15$