1. The problem is to find the equation of the line passing through the points (0,6) and (3,0). 2. The general form of a line is given by the equation $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept. 3. To find the slope $m$, use the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ where $(x_1, y_1) = (0,6)$ and $(x_2, y_2) = (3,0)$. 4. Calculate the slope: $$m = \frac{0 - 6}{3 - 0} = \frac{-6}{3} = -2$$ 5. The y-intercept $c$ is the value of $y$ when $x=0$. From the point (0,6), we see that $c = 6$. 6. Substitute $m = -2$ and $c = 6$ into the equation: $$y = -2x + 6$$ 7. This is the equation of the line passing through the given points with a negative slope. Final answer: $$y = -2x + 6$$