1. The problem asks to find the equation of a line in the form $y = mx + c$ given two points on the line. 2. The general form is $y = mx + c$, where $m$ is the slope and $c$ is the y-intercept. 3. From the graph, the line crosses the y-axis at $(0, -4)$, so $c = -4$. 4. The line passes through the points $(0, -4)$ and approximately $(1, 4)$. 5. Calculate the slope $m$ using the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - (-4)}{1 - 0} = \frac{8}{1} = 8$$ 6. Substitute $m = 8$ and $c = -4$ into the equation: $$y = 8x - 4$$ 7. Therefore, the equation of the line is $y = 8x - 4$.