1. **State the problem:** Find the equation of the line passing through points $(-2, -8)$ and $(2, 8)$ in slope-intercept form $y = mx + b$. 2. **Find the slope $m$:** Use the formula for slope between two points $(x_1, y_1)$ and $(x_2, y_2)$: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ Substitute the points: $$m = \frac{8 - (-8)}{2 - (-2)} = \frac{8 + 8}{2 + 2} = \frac{16}{4} = 4$$ 3. **Use the slope-intercept form:** $$y = mx + b$$ We know $m = 4$, so: $$y = 4x + b$$ 4. **Find $b$ (the y-intercept):** Substitute one point, for example $(-2, -8)$, into the equation: $$-8 = 4(-2) + b$$ $$-8 = -8 + b$$ Add 8 to both sides: $$0 = b$$ 5. **Write the final equation:** $$y = 4x$$ This is the equation of the line in slope-intercept form.