1. We are given that $p$ and $q$ are prime numbers with $p > q$, and their least common multiple (LCM) is 319. 2. Since $p$ and $q$ are prime, their LCM is simply their product: $$\text{LCM}(p, q) = p \times q = 319.$$ 3. We need to find two prime numbers whose product is 319. Let's factorize 319: 4. Checking divisibility by small primes: - 319 divided by 11 is 29, since $11 \times 29 = 319$ 5. Both 11 and 29 are prime numbers, and $29 > 11$, so $p = 29$ and $q = 11$. 6. The problem asks for the difference between thrice of $q$ and $p$: $$3q - p = 3 \times 11 - 29 = 33 - 29 = 4.$$ 7. Therefore, the answer is $4$, which corresponds to option C. Final answer: 4