1. **State the problem:** We need to find the cost of a snack-size bag of chips, a bottle of water, and a gallon of milk given the total cost and relationships between their prices. 2. **Define variables:** Let $c$ be the cost of a bag of chips. 3. **Express other costs in terms of $c$:** - Cost of a bottle of water = $2c$ (twice the cost of chips). - Cost of a gallon of milk = $2c + 1.60$ (milk costs $1.60 more than water). 4. **Write the total cost equation:** $$3(2c + 1.60) + 6(2c) + 5(c) = 25.50$$ 5. **Simplify the equation:** $$3(2c) + 3(1.60) + 6(2c) + 5c = 25.50$$ $$6c + 4.80 + 12c + 5c = 25.50$$ $$23c + 4.80 = 25.50$$ 6. **Solve for $c$:** $$23c = 25.50 - 4.80$$ $$23c = 20.70$$ $$c = \frac{20.70}{23} = 0.90$$ 7. **Find the cost of water and milk:** - Water: $2c = 2 \times 0.90 = 1.80$ - Milk: $2c + 1.60 = 1.80 + 1.60 = 3.40$ **Final answers:** - Snack-size bag of chips costs $0.90$ - Bottle of water costs $1.80$ - Gallon of milk costs $3.40$