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Investment Previous Close

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Investment Previous Close


1. Stating the problem: Sydney and Ann invested a total of 232212 in the ratio 1:2, find how much Ann invested. 2. Let Sydney's investment be $x$. 3. Then Ann's investment is $2x$. 4. Total investment is $x + 2x = 3x$. 5. Given total investment is 232212, so $3x = 232212$. 6. Solving for $x$, we get $x = \frac{232212}{3} = 77404$. 7. Ann's investment is $2x = 2 \times 77404 = 154808$. 8. Stating the problem: Texas Instruments closed at 28.84 which is a 5.22% increase from the previous day's close. Find the previous day's close. 9. Let previous day's close be $p$. 10. We know $p + 0.0522p = 28.84$ or $1.0522p = 28.84$. 11. Solve for $p$: $p = \frac{28.84}{1.0522} \approx 27.41$. Final answers: - Ann invested 154808. - Previous day's close was approximately 27.41.