Investment Previous Close
1. Stating the problem: Sydney and Ann invested a total of 232212 in the ratio 1:2, find how much Ann invested.
2. Let Sydney's investment be $x$.
3. Then Ann's investment is $2x$.
4. Total investment is $x + 2x = 3x$.
5. Given total investment is 232212, so $3x = 232212$.
6. Solving for $x$, we get $x = \frac{232212}{3} = 77404$.
7. Ann's investment is $2x = 2 \times 77404 = 154808$.
8. Stating the problem: Texas Instruments closed at 28.84 which is a 5.22% increase from the previous day's close. Find the previous day's close.
9. Let previous day's close be $p$.
10. We know $p + 0.0522p = 28.84$ or $1.0522p = 28.84$.
11. Solve for $p$: $p = \frac{28.84}{1.0522} \approx 27.41$.
Final answers:
- Ann invested 154808.
- Previous day's close was approximately 27.41.