1. **State the problem:** Find the x-intercept, y-intercept, and slope of the equation $$4x - y = 8$$. 2. **Rewrite the equation:** To find intercepts and slope, express the equation in slope-intercept form $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept. 3. **Isolate y:** $$4x - y = 8 \implies -y = 8 - 4x \implies y = 4x - 8$$ 4. **Find the y-intercept:** The y-intercept occurs when $$x=0$$. Substitute $$x=0$$: $$y = 4(0) - 8 = -8$$ So, the y-intercept is at $$(0, -8)$$. 5. **Find the x-intercept:** The x-intercept occurs when $$y=0$$. Set $$y=0$$ and solve for $$x$$: $$0 = 4x - 8 \implies 4x = 8 \implies x = 2$$ So, the x-intercept is at $$(2, 0)$$. 6. **Determine the slope:** From the slope-intercept form $$y = 4x - 8$$, the slope $$m = 4$$. **Final answers:** - x-intercept: $$(2, 0)$$ - y-intercept: $$(0, -8)$$ - slope: $$4$$