1. We are asked to solve the inequality $$4(8 - x) \geq 3(3x - 20) - 25$$. 2. First, expand both sides using the distributive property: $$4 \times 8 - 4 \times x \geq 3 \times 3x - 3 \times 20 - 25$$ which simplifies to $$32 - 4x \geq 9x - 60 - 25$$ 3. Combine like terms on the right side: $$32 - 4x \geq 9x - 85$$ 4. Add $4x$ to both sides to get all $x$ terms on one side: $$32 \geq 9x + 4x - 85$$ which is $$32 \geq 13x - 85$$ 5. Add $85$ to both sides to isolate the term with $x$: $$32 + 85 \geq 13x$$ $$117 \geq 13x$$ 6. Divide both sides by $13$ (positive number, so inequality direction stays the same): $$\frac{117}{13} \geq x$$ 7. Simplify the fraction: $$9 \geq x$$ 8. This means the solution is all $x$ such that $$x \leq 9$$. 9. Note the handwritten note says $8 \geq x$, which is a stricter condition than our solution. Final answer: $$x \leq 9$$