1. **State the problem:** We need to graph the inequality $3x - y \leq 4$ and find three points that satisfy this condition. 2. **Rewrite the inequality:** Rearrange to a more familiar form of $y$: $$3x - y \leq 4 \implies -y \leq 4 - 3x \implies y \geq 3x - 4$$ 3. **Find points on the boundary line:** The boundary line is $y = 3x - 4$. Choosing values for $x$: - For $x=0$: $y = 3(0) - 4 = -4$, so point $(0, -4)$ - For $x=1$: $y = 3(1) - 4 = -1$, so point $(1, -1)$ - For $x=2$: $y = 3(2) - 4 = 2$, so point $(2, 2)$ 4. **Check these points satisfy the inequality:** Since the inequality requires $y \geq 3x - 4$, these boundary points satisfy it exactly. 5. **Find a point inside the inequality region:** For example, $x=0, y=0$; check if $0 \geq 3(0) - 4 \Rightarrow 0 \geq -4$ which is true. **Final answer:** Three points on the boundary line: $(0,-4)$, $(1,-1)$, $(2,2)$ and the region of the inequality includes these and points above the line such as $(0,0)$.