1. **State the problem:** We are asked to graph the inequality $-3x + 2y > 6$ and determine where the shaded region is. 2. **Rewrite the inequality:** To graph the inequality, first rewrite it in slope-intercept form ($y = mx + b$). $$-3x + 2y > 6$$ Add $3x$ to both sides: $$2y > 3x + 6$$ Divide both sides by $2$ (note: dividing by a positive number doesn't reverse the inequality): $$y > \frac{3}{2}x + 3$$ 3. **Graph the boundary line:** The boundary line is: $$y = \frac{3}{2}x + 3$$ Since the original inequality is strict ($>$ and not $\geq$), the boundary line should be dashed. 4. **Determine shading region:** Because $y$ is greater than the line, shade the region **above** this line. 5. **Summary:** The graph is a dashed line $y=\frac{3}{2}x+3$ with the region above it shaded, representing all points $(x,y)$ that satisfy $-3x + 2y > 6$. **Final answer:** $$y > \frac{3}{2}x + 3$$ and the shaded region is all points above the dashed line $y = \frac{3}{2}x + 3$.