Ig1 Cycle Test
1. Factorise fully.
(i) Factorise $27y^2 - 3$
- Take out common factor 3: $27y^2 - 3 = 3(9y^2 - 1)$
- Recognize difference of squares: $9y^2 - 1 = (3y - 1)(3y + 1)$
- Final factorisation: $3(3y - 1)(3y + 1)$
(ii) Factorise $2m - pk + 2k - pm$
- Group terms: $(2m - pm) + (2k - pk)$
- Factor common terms in each group: $m(2-p) + k(2-p)$
- Factor out common $(2-p)$: $(2-p)(m+k)$
2. Solve the equation $\frac{x - 1}{x + 1} - \frac{6}{x - 1} = 1$
- Multiply both sides by $(x+1)(x-1)$ to clear denominators:
$(x-1)(x-1) - 6(x+1) = (x+1)(x-1)$
- Expand:
$(x-1)^2 - 6(x+1) = x^2 - 1$
- Expand and simplify:
$x^2 - 2x + 1 - 6x - 6 = x^2 - 1$
$x^2 - 8x - 5 = x^2 - 1$
- Subtract $x^2$ from both sides:
$-8x - 5 = -1$
- Add 5 to both sides:
$-8x = 4$
- Divide by $-8$:
$x = -\frac{1}{2}$
3. (a) Solve $3m + 12 \leq 8m - 5$
- Subtract $3m$ from both sides:
$12 \leq 5m - 5$
- Add 5:
$17 \leq 5m$
- Divide by 5:
$\frac{17}{5} \leq m$ or $m \geq 3.4$
(b) Solve $\frac{2x + 5}{3 - x} = \frac{14}{15}$
- Cross multiply:
$15(2x + 5) = 14(3 - x)$
- Expand:
$30x + 75 = 42 - 14x$
- Add $14x$:
$44x + 75 = 42$
- Subtract 75:
$44x = -33$
- Divide by 44:
$x = -\frac{33}{44} = -\frac{3}{4} = -0.75$
4. (c) Solve simultaneous equations:
$y = 4 - x$
$x^2 + 2y^2 = 67$
- Substitute for y:
$x^2 + 2(4 - x)^2 = 67$
- Expand:
$x^2 + 2(16 - 8x + x^2) = 67$
$x^2 + 32 -16x + 2x^2 = 67$
$3x^2 -16x + 32 = 67$
- Simplify:
$3x^2 - 16x - 35 = 0$
- Use quadratic formula $x = \frac{16 \pm \sqrt{(-16)^2 - 4 \cdot 3 \cdot (-35)}}{2 \cdot 3}$
$= \frac{16 \pm \sqrt{256 + 420}}{6} = \frac{16 \pm \sqrt{676}}{6} = \frac{16 \pm 26}{6}$
- Solutions for x:
$x = \frac{16 + 26}{6} = 7$, $x = \frac{16 - 26}{6} = -\frac{5}{3}$
- Find corresponding y:
For $x=7$, $y=4-7=-3$
For $x=-\frac{5}{3}$, $y=4 - \left(-\frac{5}{3}\right) = 4 + \frac{5}{3} = \frac{17}{3}$
5. y is inversely proportional to $(x + 1)^2$ with $y=50$ at $x=0.2$.
(a) Write $y$ in terms of $x$.
- Because $y \propto \frac{1}{(x+1)^2}$, write $y = \frac{k}{(x+1)^2}$
- Use $x=0.2$, $y=50$ to find $k$:
$50 = \frac{k}{(1.2)^2} = \frac{k}{1.44}$
$k = 50 \times 1.44 = 72$
- Final formula:
$y = \frac{72}{(x+1)^2}$
(b) Find $y$ when $x=0.5$:
$y = \frac{72}{(1.5)^2} = \frac{72}{2.25} = 32$
6. (a) Factorise $x^2 - 3x - 10$
- Find factors of $-10$ that sum to $-3$: $-5$ and $2$
- Factorise:
$(x - 5)(x + 2)$
(b)(i) Show that $\frac{x+2}{x+1} + \frac{3}{x} = 3$ simplifies to $2x^2 - 2x - 3 = 0$.
- Multiply both sides by $x(x+1)$ to clear denominators:
$x(x+1) \left( \frac{x+2}{x+1} + \frac{3}{x} \right) = 3x(x+1)$
- Distribute:
$x(x+2) + 3(x+1) = 3x(x+1)$
- Expand:
$x^2 + 2x + 3x + 3 = 3x^2 + 3x$
- Simplify left side:
$x^2 + 5x + 3 = 3x^2 + 3x$
- Move all terms to one side:
$0 = 3x^2 + 3x - x^2 - 5x - 3 = 2x^2 - 2x - 3$
- Hence, the equation reduces to:
$2x^2 - 2x - 3 = 0$