1. The problem is to graph the line given by the slope-intercept form equation $$y = -\frac{1}{3}x + 5$$. 2. The slope-intercept form of a line is $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. Here, the slope $m = -\frac{1}{3}$ means the line falls 1 unit vertically for every 3 units it moves horizontally to the right. 4. The y-intercept $b = 5$ means the line crosses the y-axis at the point $(0, 5)$. 5. To graph, start at $(0, 5)$ on the y-axis. 6. From $(0, 5)$, move right 3 units and down 1 unit to get the next point $(3, 4)$. 7. Draw a straight line through these points extending in both directions. 8. The line will slope downward from left to right because the slope is negative. Final answer: The graph of $$y = -\frac{1}{3}x + 5$$ is a line crossing the y-axis at 5 and sloping downward with slope $-\frac{1}{3}$.