1. **Problem statement:** Given the function $f(x) = \sqrt{x}$ and its graph $K_f$, we want to find how the graph $K_h$ of $h(x)$ is derived from $f(x)$. 2. **Understanding transformations:** The graph $K_h$ appears as a reflection of $K_f$ across the x-axis, indicating a vertical reflection. This means $h(x) = -f(x)$. 3. **Write the function equation:** Since $f(x) = \sqrt{x}$, the reflected function is $$h(x) = -\sqrt{x}.$$ 4. **Verification:** Check points from $f(x)$ and $h(x)$: - For $x=0$, $f(0) = 0$, so $h(0) = -0 = 0$. - For $x=1$, $f(1) = 1$, so $h(1) = -1$. - For $x=4$, $f(4) = 2$, so $h(4) = -2$. These points match the description of $K_h$ passing through $(0,0)$ and negative y-values as $x$ increases. 5. **Conclusion:** The graph $K_h$ is the reflection of $K_f$ across the x-axis, and the function is $$h(x) = -\sqrt{x}.$$