1. The problem is to draw the graphs of the two linear equations: $$x - 5y = 6$$ $$3x - 5y = 9$$ 2. To graph these lines, we first rewrite each equation in slope-intercept form $y = mx + b$ where $m$ is the slope and $b$ is the y-intercept. 3. For the first equation: $$x - 5y = 6 \implies -5y = 6 - x \implies y = \frac{x}{5} - \frac{6}{5}$$ 4. For the second equation: $$3x - 5y = 9 \implies -5y = 9 - 3x \implies y = \frac{3x}{5} - \frac{9}{5}$$ 5. Now we have: - Line 1: $y = \frac{1}{5}x - \frac{6}{5}$ - Line 2: $y = \frac{3}{5}x - \frac{9}{5}$ 6. These are straight lines with slopes $\frac{1}{5}$ and $\frac{3}{5}$ respectively, and y-intercepts $-\frac{6}{5}$ and $-\frac{9}{5}$. 7. To graph, plot the y-intercepts on the y-axis and use the slope to find another point for each line. Final answer: - Line 1: $y = \frac{1}{5}x - \frac{6}{5}$ - Line 2: $y = \frac{3}{5}x - \frac{9}{5}$