1. The problem asks: If the airplane flew 35 miles, how many gallons of gas would be left in the tank? 2. From the graph description, the gas remaining decreases linearly from about 9 gallons at 0 miles to about 3.5 gallons at 40 miles. 3. We can find the equation of the line relating gas remaining $G$ to distance flown $d$ using the two points: $(0,9)$ and $(40,3.5)$. 4. The slope $m$ of the line is given by: $$m = \frac{3.5 - 9}{40 - 0} = \frac{-5.5}{40} = -0.1375$$ 5. The linear equation in point-slope form is: $$G - 9 = -0.1375(d - 0)$$ which simplifies to: $$G = 9 - 0.1375d$$ 6. To find the gas remaining after flying 35 miles, substitute $d = 35$: $$G = 9 - 0.1375 \times 35 = 9 - 4.8125 = 4.1875$$ 7. Therefore, approximately 4.19 gallons of gas would be left after flying 35 miles.