Subjects algebra

Frame Length 59Fa5D

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Frame Length 59Fa5D


1. The problem asks for the length of the frame shown on the number line, expressed as both a mixed number and an improper fraction. 2. The frame extends from 1 to 5 on the number line. To find the length, subtract the starting point from the ending point: $$\text{Length} = 5 - 1 = 4$$ 3. The length is 4 units. Since 4 is a whole number, it can be written as a mixed number as $4\frac{0}{1}$ or simply 4. 4. To express 4 as an improper fraction, write it as: $$4 = \frac{4}{1}$$ 5. Therefore, the length of the frame is 4 as a mixed number and $\frac{4}{1}$ as an improper fraction.