Fraction Subtraction A91Ce8
1. **State the problem:** Simplify the expression $$\frac{x + 1}{2x + 9} - \frac{2x + 3}{4x - 1}$$.
2. **Find a common denominator:** The denominators are $2x + 9$ and $4x - 1$. The common denominator is their product: $$(2x + 9)(4x - 1)$$.
3. **Rewrite each fraction with the common denominator:**
$$\frac{x + 1}{2x + 9} = \frac{(x + 1)(4x - 1)}{(2x + 9)(4x - 1)}$$
$$\frac{2x + 3}{4x - 1} = \frac{(2x + 3)(2x + 9)}{(4x - 1)(2x + 9)}$$
4. **Subtract the numerators:**
$$\frac{(x + 1)(4x - 1) - (2x + 3)(2x + 9)}{(2x + 9)(4x - 1)}$$
5. **Expand the numerators:**
$$(x + 1)(4x - 1) = 4x^2 - x + 4x - 1 = 4x^2 + 3x - 1$$
$$(2x + 3)(2x + 9) = 4x^2 + 18x + 6x + 27 = 4x^2 + 24x + 27$$
6. **Subtract the expanded numerators:**
$$4x^2 + 3x - 1 - (4x^2 + 24x + 27) = 4x^2 + 3x - 1 - 4x^2 - 24x - 27 = -21x - 28$$
7. **Write the simplified expression:**
$$\frac{-21x - 28}{(2x + 9)(4x - 1)}$$
8. **Factor the numerator:**
$$-21x - 28 = -7(3x + 4)$$
9. **Final simplified form:**
$$\frac{-7(3x + 4)}{(2x + 9)(4x - 1)}$$
This is the simplified expression for the given subtraction of fractions.