1. The problem is to verify if $$\left( \frac{4}{5} \right)^2 = \frac{25}{16}$$ is true. 2. The formula for squaring a fraction is $$\left( \frac{a}{b} \right)^2 = \frac{a^2}{b^2}$$ where $a$ and $b$ are numbers. 3. Applying this formula, we square the numerator and denominator separately: $$\left( \frac{4}{5} \right)^2 = \frac{4^2}{5^2} = \frac{16}{25}$$ 4. Comparing the result $$\frac{16}{25}$$ with the given $$\frac{25}{16}$$, we see they are not equal. 5. Therefore, the statement $$\left( \frac{4}{5} \right)^2 = \frac{25}{16}$$ is false. Final answer: $$\left( \frac{4}{5} \right)^2 = \frac{16}{25} \neq \frac{25}{16}$$