1. The problem asks to evaluate the expression $$\frac{\sqrt[3]{5} - \sqrt{3}}{\sqrt[3]{5} - \sqrt{3}}$$. 2. Notice that the numerator and denominator are identical. 3. Any nonzero number divided by itself equals 1. 4. Since $$\sqrt[3]{5} - \sqrt{3}$$ is not zero (because cube root of 5 and square root of 3 are different), 5. Therefore, $$\frac{\sqrt[3]{5} - \sqrt{3}}{\sqrt[3]{5} - \sqrt{3}} = 1$$. **Final answer:** 1