Subjects algebra

Fraction C B

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Fraction C B


1. **State the problem:** We are given three numbers, A, B, and C. B is \(\frac{7}{4}\) of A, meaning \(B = \frac{7}{4}A\). C is A increased by 150%, which means C is \(A\) plus 150% of \(A\). 2. **Express C in terms of A:** Increasing A by 150% means adding \(1.5 \times A\) to \(A\). So, \(C = A + 1.5A = 2.5A = \frac{5}{2}A\). 3. **Set up the ratio \(\frac{C}{B}\):** \[ \frac{C}{B} = \frac{\frac{5}{2}A}{\frac{7}{4}A} \] 4. **Simplify the fraction:** Since \(A \neq 0\), \(A\) cancels out: \[ \frac{C}{B} = \frac{\frac{5}{2}}{\frac{7}{4}} = \frac{5}{2} \times \frac{4}{7} = \frac{20}{14} = \frac{10}{7} \] **Final answer:** \[ \boxed{\frac{10}{7}} \] C as a fraction of B is \(\frac{10}{7}\).