1. Problem statement: Jawad has two fish tanks, one larger and one smaller. The smaller tank initially has 35 fish. If 15 fish are transferred from the larger to the smaller tank, the smaller tank then has fish equal to $\frac{3}{5}$ of the larger tank's fish after transfer. We need to find the number of fish in the larger tank before the transfer. 2. Let the number of fish in the larger tank before transfer be $x$. 3. After transfer, the larger tank has $x - 15$ fish. 4. After transfer, the smaller tank has $35 + 15 = 50$ fish. 5. According to the problem, the smaller tank fish equals $\frac{3}{5}$ the larger tank fish after transfer: $$50 = \frac{3}{5}(x - 15)$$ 6. Multiply both sides by 5: $$250 = 3(x - 15)$$ 7. Expand the right side: $$250 = 3x - 45$$ 8. Add 45 to both sides: $$250 + 45 = 3x$$ $$295 = 3x$$ 9. Divide both sides by 3: $$x = \frac{295}{3} = 98\frac{1}{3}$$ 10. Since the number of fish must be an integer, we interpret $x = 98$ fish (possibly rounding or problem expects whole number). **Final answer:** Jawad originally had 98 fish in the larger tank before the transfer.