1. The problem states that a pie chart represents three uniform units: Scouts (Pengakap), Police Cadets (Kadet Polis), and KRS, with given numbers for Scouts (45) and KRS (115). We need to find the angle $x$ corresponding to the Scouts sector. 2. Recall that the total angle in a pie chart is $360^\circ$ and the angle for each sector is proportional to the number of members in that unit. 3. Let the number of Police Cadets be $P$. The total number of members is $45 + 115 + P = 160 + P$. 4. The angle for Scouts is given as $x^\circ$, and the problem shows it as a right angle sector, so $x$ is the angle for Scouts. 5. The angle for Scouts can be calculated by the formula: $$x = \frac{\text{Number of Scouts}}{\text{Total number}} \times 360^\circ = \frac{45}{160 + P} \times 360^\circ$$ 6. The angle for KRS is: $$\text{Angle for KRS} = \frac{115}{160 + P} \times 360^\circ$$ 7. The angle for Police Cadets is the remaining angle: $$\text{Angle for Police Cadets} = 360^\circ - x - \text{Angle for KRS}$$ 8. The problem states the Scouts sector has a right angle symbol, so $x = 90^\circ$. 9. Using $x = 90^\circ$, solve for $P$: $$90 = \frac{45}{160 + P} \times 360$$ 10. Simplify: $$90 = \frac{45 \times 360}{160 + P}$$ $$90 (160 + P) = 45 \times 360$$ $$14400 + 90P = 16200$$ 11. Solve for $P$: $$90P = 16200 - 14400 = 1800$$ $$P = \frac{1800}{90} = 20$$ 12. The angle $x$ is $90^\circ$, but the question asks for $x$ which is the angle for Scouts. Since the problem states $x^\circ$ is the angle for Scouts and the right angle symbol is shown, $x = 90^\circ$. 13. However, the options given are 20, 40, 60, 80. Since $x=90$ is not an option, we must reconsider. 14. The problem states the Scouts sector has angle $x^\circ$ and a right angle symbol, but the right angle symbol might be for the Police Cadet sector (not explicitly clear). Given the data, let's calculate $x$ assuming the total members are $45 + 115 + P$ and the total angle is $360^\circ$. 15. The sum of angles is $360^\circ$, so: $$x + \text{Angle for Police Cadet} + \text{Angle for KRS} = 360^\circ$$ 16. The angle for KRS is: $$\frac{115}{45 + 115 + P} \times 360 = \frac{115}{160 + P} \times 360$$ 17. The angle for Scouts is: $$x = \frac{45}{160 + P} \times 360$$ 18. The angle for Police Cadet is: $$\text{Angle for Police Cadet} = \frac{P}{160 + P} \times 360$$ 19. Since the pie chart is complete: $$x + \frac{P}{160 + P} \times 360 + \frac{115}{160 + P} \times 360 = 360$$ 20. Simplify: $$\frac{45}{160 + P} \times 360 + \frac{P}{160 + P} \times 360 + \frac{115}{160 + P} \times 360 = 360$$ $$\frac{45 + P + 115}{160 + P} \times 360 = 360$$ $$\frac{160 + P}{160 + P} \times 360 = 360$$ 21. This confirms the total angle is $360^\circ$. 22. Now, calculate $x$: $$x = \frac{45}{45 + 115 + P} \times 360 = \frac{45}{160 + P} \times 360$$ 23. The problem states the angle for Police Cadet is $x^\circ$, so $x$ corresponds to Police Cadet, not Scouts. 24. Given that, the angle for Police Cadet is $x$, and the number of Police Cadet members is $P$. 25. Using the ratio of angles to members: $$x = \frac{P}{45 + 115 + P} \times 360 = \frac{P}{160 + P} \times 360$$ 26. The sum of angles for Scouts and KRS is: $$\text{Angle for Scouts} + \text{Angle for KRS} = 90^\circ + \text{Angle for KRS}$$ 27. The problem shows the Scouts sector with a right angle symbol, so Scouts angle is $90^\circ$. 28. Calculate the angle for KRS: $$\text{Angle for KRS} = \frac{115}{160 + P} \times 360$$ 29. Sum of angles: $$90 + \frac{115}{160 + P} \times 360 + x = 360$$ 30. Substitute $x$: $$90 + \frac{115}{160 + P} \times 360 + \frac{P}{160 + P} \times 360 = 360$$ 31. Simplify: $$90 + \frac{(115 + P) \times 360}{160 + P} = 360$$ 32. Multiply both sides by $160 + P$: $$90 (160 + P) + 360 (115 + P) = 360 (160 + P)$$ 33. Expand: $$14400 + 90P + 41400 + 360P = 57600 + 360P$$ 34. Combine like terms: $$55800 + 450P = 57600 + 360P$$ 35. Subtract $360P$ and $55800$ from both sides: $$450P - 360P = 57600 - 55800$$ $$90P = 1800$$ 36. Solve for $P$: $$P = \frac{1800}{90} = 20$$ 37. Now find $x$: $$x = \frac{P}{160 + P} \times 360 = \frac{20}{180} \times 360 = \frac{1}{9} \times 360 = 40^\circ$$ 38. Therefore, the value of $x$ is $40^\circ$. **Final answer: 40**