1. **Stating the problem:** You want to fill columns KOLOM 1 to KOLOM 4 with random values such that the average (rata-rata) column matches the given values. 2. **Formula used:** The average for each row is calculated as $$\text{rata-rata} = \frac{\text{KOLOM 1} + \text{KOLOM 2} + \text{KOLOM 3} + \text{KOLOM 4}}{4}$$ 3. **Important rule:** To find the sum of the four columns for each row, multiply the average by 4: $$\text{Sum} = 4 \times \text{rata-rata}$$ 4. **Approach:** We will generate four random integers for each row such that their sum equals the calculated sum from the average. 5. **Example for one row:** Suppose the average is 80 for a row. Then, $$\text{Sum} = 4 \times 80 = 320$$ We generate four random numbers $a,b,c,d$ such that $$a + b + c + d = 320$$ 6. **General method:** - For each row, calculate $S = 4 \times \text{rata-rata}$. - Generate three random integers $a,b,c$ between reasonable ranges. - Calculate $d = S - (a+b+c)$. - Ensure $d$ is within the valid range (e.g., 0 to 100). - If not, regenerate $a,b,c$. 7. **This ensures the average column remains consistent with the generated values.** Since the user requested only the method and explanation, actual random values are not generated here. Final answer: Use the formula $$\text{rata-rata} = \frac{\text{KOLOM 1} + \text{KOLOM 2} + \text{KOLOM 3} + \text{KOLOM 4}}{4}$$ and generate random values in KOLOM 1 to KOLOM 4 such that their sum equals $4 \times \text{rata-rata}$ for each row.