1. **Problem Statement:** A farmer buys 54 bags of fertilizer A and 34 bags of fertilizer B. Fertilizer A contains 3 kg nitrogen, 1 kg potassium, 2 kg potash per bag. Fertilizer B contains 2 kg nitrogen, 0 kg potassium, 1 kg potash per bag. Find total kgs of nitrogen, potassium, and potash supplied. 2. **Formula:** Total nutrient = (bags of A) \times (nutrient per A) + (bags of B) \times (nutrient per B) 3. **Calculate nitrogen:** $$\text{Nitrogen} = 54 \times 3 + 34 \times 2 = 162 + 68 = 230$$ 4. **Calculate potassium:** $$\text{Potassium} = 54 \times 1 + 34 \times 0 = 54 + 0 = 54$$ 5. **Calculate potash:** $$\text{Potash} = 54 \times 2 + 34 \times 1 = 108 + 34 = 142$$ 6. **Answer:** The farmer should mix together 230 kg nitrogen, 54 kg potassium, and 142 kg potash to supply the necessary nutrients. None of the given options match these values exactly, so the correct choice is E) None.