1. The problem states that the area of Fairuz's land is 3600 m², and the land is rectangular with sides $x$ meters and $(2x + 10)$ meters. 2. The area formula for a rectangle is: $$\text{Area} = \text{length} \times \text{width}$$ Here, the area is given as 3600 m², so: $$x(2x + 10) = 3600$$ 3. Expand and simplify the equation: $$2x^2 + 10x = 3600$$ 4. Rearrange to standard quadratic form: $$2x^2 + 10x - 3600 = 0$$ Divide the entire equation by 2 to simplify: $$x^2 + 5x - 1800 = 0$$ 5. Solve the quadratic equation using the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a=1$, $b=5$, and $c=-1800$. Calculate the discriminant: $$\Delta = 5^2 - 4(1)(-1800) = 25 + 7200 = 7225$$ Calculate the square root: $$\sqrt{7225} = 85$$ 6. Find the two possible values for $x$: $$x = \frac{-5 \pm 85}{2}$$ - For the positive root: $$x = \frac{-5 + 85}{2} = \frac{80}{2} = 40$$ - For the negative root: $$x = \frac{-5 - 85}{2} = \frac{-90}{2} = -45$$ Since length cannot be negative, we take $x = 40$ meters. 7. Calculate the other side: $$2x + 10 = 2(40) + 10 = 80 + 10 = 90$$ meters. 8. Calculate the perimeter of the land (the total length of the fence): $$P = 2(x + 2x + 10) = 2(40 + 90) = 2(130) = 260$$ meters. 9. Calculate the cost of building the fence: $$\text{Cost} = \text{perimeter} \times \text{price per meter} = 260 \times 25 = 6500$$ 10. Compare the cost with the savings: Savings = 6500 Cost = 6500 Since the cost equals the savings, the remaining money is zero, so the savings are just enough to build the fence. **Final answer:** - The cost of building the fence is 6500. - The savings of 6500 are sufficient to cover the cost exactly, with no remaining balance.