1. The problem asks us to find all factors of 40. 2. A factor of a number is any integer that divides that number exactly without leaving a remainder. 3. To find factors of 40, we test all integers from 1 up to 40. 4. Divide 40 by each number and check if the remainder is 0: - $40 \div 1 = 40$, remainder 0, so 1 is a factor. - $40 \div 2 = 20$, remainder 0, so 2 is a factor. - $40 \div 3 = 13.333...$, remainder not 0, so 3 is not a factor. - $40 \div 4 = 10$, remainder 0, so 4 is a factor. - $40 \div 5 = 8$, remainder 0, so 5 is a factor. - $40 \div 6 = 6.666...$, not a factor. - $40 \div 7 = 5.714...$, not a factor. - $40 \div 8 = 5$, remainder 0, so 8 is a factor. - $40 \div 9 = 4.444...$, not a factor. - $40 \div 10 = 4$, remainder 0, so 10 is a factor. - $40 \div 11$ to $40 \div 19$ all leave remainders, so not factors. - $40 \div 20 = 2$, remainder 0, so 20 is a factor. - $40 \div 40 = 1$, remainder 0, so 40 is a factor. 5. Collecting all, the factors of 40 are: $1, 2, 4, 5, 8, 10, 20, 40$. 6. These are all the integers that divide 40 without any remainder, hence the complete set of factors.