1. **State the problem:** Factorize completely the expression $$x^4 - x^2$$.
2. **Identify the common factor:** Notice that both terms have a common factor of $$x^2$$. So, we can factor out $$x^2$$:
$$x^4 - x^2 = x^2(x^2 - 1)$$.
3. **Recognize the difference of squares:** The expression inside the parentheses, $$x^2 - 1$$, is a difference of squares since $$1 = 1^2$$. The difference of squares formula is:
$$a^2 - b^2 = (a - b)(a + b)$$.
4. **Apply the difference of squares formula:**
$$x^2 - 1 = (x - 1)(x + 1)$$.
5. **Write the complete factorization:**
$$x^4 - x^2 = x^2(x - 1)(x + 1)$$.
6. **Compare with the options:**
- Option A: $$x(x - 1)(x + 1)$$ (missing one $$x$$ factor)
- Option B: $$(x^2 - 1)(x^2 + 1)$$ (incorrect factorization)
- Option C: $$x^2(x^2 - 1)$$ (partially factored, not fully)
- Option D: $$(x^2 - x)(x^2 + x)$$ (incorrect)
The fully factorized form matches option C, but since $$x^2 - 1$$ can be further factored, the complete factorization is $$x^2(x - 1)(x + 1)$$ which is not exactly listed. However, option C is the correct intermediate step.
**Final answer:** $$x^2(x^2 - 1)$$ (Option C)
Factorize Polynomial B16350
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