Factorize Difference Squares
1. We are asked to factorize the expression $$(2x + 9)^2 - (x + 4)^2$$.
2. Recognize this as a difference of squares, which has the formula $$a^2 - b^2 = (a - b)(a + b)$$.
3. Let $$a = 2x + 9$$ and $$b = x + 4$$.
4. Then the expression can be written as $$(2x + 9 - (x + 4))(2x + 9 + (x + 4))$$.
5. Simplify each factor:
- First factor: $$2x + 9 - x - 4 = (2x - x) + (9 - 4) = x + 5$$
- Second factor: $$2x + 9 + x + 4 = (2x + x) + (9 + 4) = 3x + 13$$
6. Therefore, the fully factorized form is $$ (x + 5)(3x + 13) $$.
Final answer: $$ (x + 5)(3x + 13) $$.