1. The problem asks to find the value of $5!$. 2. The factorial of a positive integer $n$, denoted $n!$, is the product of all positive integers from 1 to $n$. 3. The formula is: $$n! = n \times (n-1) \times (n-2) \times \cdots \times 2 \times 1$$ 4. For $5!$, we calculate: $$5! = 5 \times 4 \times 3 \times 2 \times 1$$ 5. Multiply step-by-step: $$5 \times 4 = 20$$ $$20 \times 3 = 60$$ $$60 \times 2 = 120$$ $$120 \times 1 = 120$$ 6. Therefore, the value of $5!$ is $120$.