1. The problem asks to factor the quadratic expression $y = t^2 + 2t - 48$. 2. To factor, we look for two numbers that multiply to the constant term $-48$ and add to the coefficient of $t$, which is $2$. 3. The pair of numbers that satisfy this are $8$ and $-6$, since $8 \times (-6) = -48$ and $8 + (-6) = 2$. 4. Therefore, the factored form is $$y = (t + 8)(t - 6).$$ 5. Comparing with the options, the correct factorization is $y = (t - 6)(t + 8)$.