Factor Quadratic 31A6B5
1. **State the problem:** Factor the expression $4x^2 - 16$ and draw its graph.
2. **Formula and rules:** To factor expressions like $a^2 - b^2$, use the difference of squares formula:
$$a^2 - b^2 = (a - b)(a + b)$$
This applies because both terms are perfect squares.
3. **Apply the formula:**
First, recognize that $4x^2 = (2x)^2$ and $16 = 4^2$.
So,
$$4x^2 - 16 = (2x)^2 - 4^2$$
Using the difference of squares,
$$= (2x - 4)(2x + 4)$$
4. **Simplify factors:**
Factor out 2 from each binomial:
$$(2x - 4) = 2(x - 2)$$
$$(2x + 4) = 2(x + 2)$$
So,
$$(2x - 4)(2x + 4) = 2(x - 2) imes 2(x + 2) = 4(x - 2)(x + 2)$$
5. **Final factored form:**
$$4x^2 - 16 = 4(x - 2)(x + 2)$$
6. **Graph explanation:**
The original expression $y = 4x^2 - 16$ is a parabola opening upwards with vertex at $(0, -16)$.
The roots (x-intercepts) are found by setting $y=0$:
$$4x^2 - 16 = 0 \Rightarrow x^2 = 4 \Rightarrow x = \pm 2$$
This matches the factors $(x - 2)$ and $(x + 2)$.