1. The problem asks to write the expression $-x^{1/3} + \frac{9}{7} \cdot 2$ as one fraction with positive exponents. 2. First, simplify the constant multiplication: $\frac{9}{7} \cdot 2 = \frac{18}{7}$. 3. The expression becomes $-x^{1/3} + \frac{18}{7}$. 4. To write this as one fraction, find a common denominator. The term $-x^{1/3}$ can be written as $\frac{-x^{1/3} \cdot 7}{7} = \frac{-7x^{1/3}}{7}$. 5. Now the expression is $\frac{-7x^{1/3}}{7} + \frac{18}{7} = \frac{-7x^{1/3} + 18}{7}$. 6. The exponent $1/3$ is already positive, so no change is needed there. 7. Final answer: $$\frac{18 - 7x^{1/3}}{7}$$