Expression Curve 423Dcd
1. The problem is to simplify and understand the expression $$\frac{2 \left( \frac{2e^{2} - 1}{2ze} + Pn(2e) \right)}{(2e + 1)^{2}}$$ and then plot its curve.
2. The expression involves exponential terms, a function $Pn(2e)$, and algebraic fractions.
3. First, rewrite the numerator by distributing the 2:
$$2 \times \frac{2e^{2} - 1}{2ze} + 2 \times Pn(2e) = \frac{2(2e^{2} - 1)}{2ze} + 2 Pn(2e)$$
4. Simplify the fraction:
$$\frac{2(2e^{2} - 1)}{2ze} = \frac{2e^{2} - 1}{ze}$$
5. So the numerator becomes:
$$\frac{2e^{2} - 1}{ze} + 2 Pn(2e)$$
6. The denominator is:
$$(2e + 1)^{2}$$
7. Therefore, the full expression is:
$$\frac{\frac{2e^{2} - 1}{ze} + 2 Pn(2e)}{(2e + 1)^{2}}$$
8. To plot this curve, we treat $e$ as the variable and $z$ and $Pn(2e)$ as given functions or constants depending on context.
9. The Desmos-compatible function for plotting is:
$$y=\frac{\frac{2e^{2} - 1}{ze} + 2 Pn(2e)}{(2e + 1)^{2}}$$
Final simplified expression ready for plotting:
$$y=\frac{\frac{2e^{2} - 1}{ze} + 2 Pn(2e)}{(2e + 1)^{2}}$$