1. The problem provides the function $p(t) = 600(1.025)^t$. 2. This is an exponential growth function where $600$ is the initial amount and $1.025$ is the growth factor. 3. At time $t=0$, the quantity is $p(0) = 600(1.025)^0 = 600 \times 1 = 600$. 4. For any time $t$, the population or quantity is found by multiplying $600$ by $1.025$ to the power of $t$. 5. This model indicates the amount grows by $2.5\%$ each unit time because $1.025 = 1 + 0.025$. 6. No further simplification is needed unless you want to calculate specific values for $t$. Final answer: The exponential growth function is $p(t) = 600(1.025)^t$ with initial value $600$ and growth rate $2.5\%$ per time unit.