Exponential Graph Match E25Cb5
1. The problem is to match each given function with its corresponding graph based on the description of their shapes.
2. The functions are:
- $t(x) = \frac{2}{3}3^x$
- $h(x) = -\frac{2}{3}3^x$
- $q(x) = \frac{2}{3}\left(\frac{1}{2}\right)^x$
- $v(x) = -\frac{2}{3}\left(\frac{1}{2}\right)^x$
3. Important rules:
- Exponential growth occurs when the base of the exponent is greater than 1.
- Exponential decay occurs when the base is between 0 and 1.
- A negative coefficient reflects the graph across the x-axis.
4. Analyze each function:
- $t(x) = \frac{2}{3}3^x$: base 3 > 1, positive coefficient, so exponential growth starting near 0 for negative $x$ and increasing rapidly.
- $h(x) = -\frac{2}{3}3^x$: base 3 > 1, negative coefficient, so exponential growth reflected below x-axis, starting near 0 for negative $x$ and decreasing rapidly to negative values.
- $q(x) = \frac{2}{3}\left(\frac{1}{2}\right)^x$: base $\frac{1}{2} < 1$, positive coefficient, so exponential decay starting high for negative $x$ and approaching 0 as $x$ increases.
- $v(x) = -\frac{2}{3}\left(\frac{1}{2}\right)^x$: base $\frac{1}{2} < 1$, negative coefficient, so exponential decay reflected below x-axis, starting low (negative) for negative $x$ and approaching 0 from below as $x$ increases.
5. Match with graphs:
- Top-left graph: exponential growth near 0 for negative $x$, increasing rapidly to 10 at $x=2$ matches $t(x)$.
- Top-right graph: exponential growth reflected below x-axis, decreasing to about -10 at $x=10$ matches $h(x)$.
- Bottom-left graph: exponential decay starting near 10 at $x=-10$, approaching 0 matches $q(x)$.
- Bottom-right graph: exponential decay reflected below x-axis, starting near -10 at $x=-10$, approaching 0 matches $v(x)$.
Final answer:
- Top-left: $t(x) = \frac{2}{3}3^x$
- Top-right: $h(x) = -\frac{2}{3}3^x$
- Bottom-left: $q(x) = \frac{2}{3}\left(\frac{1}{2}\right)^x$
- Bottom-right: $v(x) = -\frac{2}{3}\left(\frac{1}{2}\right)^x$