Exponential Equation 01B33D
1. **State the problem:** Solve the equation $$(0.25)^x = 16$$ for $x$.
2. **Recall the formula and rules:** We use the property of exponents that if $$a^x = a^y$$, then $$x = y$$, provided $$a > 0$$ and $$a \neq 1$$.
3. **Rewrite the bases as powers of the same number:** Note that $$0.25 = \frac{1}{4} = 4^{-1}$$ and $$16 = 4^2$$.
4. **Substitute these into the equation:**
$$ (4^{-1})^x = 4^2 $$
5. **Simplify the left side using the power of a power rule:**
$$ 4^{-x} = 4^2 $$
6. **Since the bases are equal, set the exponents equal:**
$$ -x = 2 $$
7. **Solve for $$x$$:**
$$ x = -2 $$
**Final answer:** $$x = -2$$