Exponent Laws
1. **Stating the problem:** Simplify each expression by applying the laws of exponents in parts (c), (d), and (e).
2. **Part (c): Simplify \((u^{-1} v / v^{-1})^2\)**
First, rewrite the expression separating numerator and denominator:
$$\left(\frac{u^{-1} v}{v^{-1}}\right)^2 = \frac{(u^{-1} v)^2}{(v^{-1})^2}$$
Apply exponent rules inside numerator and denominator:
$$= \frac{u^{-2} v^2}{v^{-2}}$$
Use the quotient rule for exponents on \(v\):
$$= u^{-2} v^{2 - (-2)} = u^{-2} v^4$$
Rewrite negative exponent in denominator form:
$$= \frac{v^4}{u^2}$$
3. **Part (d): Simplify \((-2a^3 b^{-1})(5a^{-2} b^2)\)**
Multiply coefficients and variables separately:
$$= (-2) \cdot 5 \cdot a^{3 + (-2)} \cdot b^{-1 + 2}$$
Calculate exponents:
$$= -10 \cdot a^{1} \cdot b^{1} = -10ab$$
4. **Part (e): Simplify \((x^2 \sqrt{2})^4 (x^2 \sqrt{2})^{-4}\)**
Use the product of powers property:
$$= (x^2 \sqrt{2})^{4 + (-4)} = (x^2 \sqrt{2})^{0}$$
Any quantity raised to the zero power equals 1:
$$= 1$$
**Final answers:**
- (c) $$\frac{v^4}{u^2}$$
- (d) $$-10ab$$
- (e) $$1$$