Evaluate Expression B9C310
1. **Stating the problem:**
We need to evaluate the expression:
$$N' = \left[ \frac{k}{s} \sqrt{N \frac{\Sigma (Y^2) - (\Sigma x)^2}{\Sigma X}} \right] = \left[ \frac{2}{0.05} \sqrt{5 (17986.5) - 90000} \div 300 \right]^2$$
2. **Identify given values:**
- $k = 2$
- $s = 0.05$
- $N = 5$
- $\Sigma (Y^2) = 17986.5$
- $(\Sigma x)^2 = 90000$
- $\Sigma X = 300$
3. **Calculate the expression inside the square root:**
$$5 \times 17986.5 - 90000 = 89932.5 - 90000 = -67.5$$
4. **Evaluate the square root:**
Since the value inside the square root is negative ($-67.5$), the expression involves an imaginary number:
$$\sqrt{-67.5} = i \sqrt{67.5}$$
5. **Calculate the fraction outside the root:**
$$\frac{k}{s} = \frac{2}{0.05} = 40$$
6. **Calculate the entire bracket before squaring:**
$$40 \times \frac{i \sqrt{67.5}}{300} = \frac{40}{300} i \sqrt{67.5} = \frac{2}{15} i \sqrt{67.5}$$
7. **Square the entire expression:**
$$\left( \frac{2}{15} i \sqrt{67.5} \right)^2 = \left( \frac{2}{15} \right)^2 \times (i)^2 \times (\sqrt{67.5})^2 = \frac{4}{225} \times (-1) \times 67.5 = -\frac{270}{225} = -1.2$$
**Final answer:**
$$N' = -1.2$$
Since the value inside the square root was negative, the result is a negative real number after squaring the imaginary term.