Subjects algebra

Elevator Distance 6Aa8E7

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Search Solutions

Elevator Distance 6Aa8E7


1. **State the problem:** We know the elevator travels 330 feet in 10 seconds. We want to find how far it travels in 11 seconds. 2. **Identify the formula:** Since the elevator moves at a constant speed, we use the formula for distance with constant speed: $$\text{Distance} = \text{Speed} \times \text{Time}$$ 3. **Calculate the speed:** Speed is distance divided by time: $$\text{Speed} = \frac{330 \text{ feet}}{10 \text{ seconds}} = 33 \text{ feet/second}$$ 4. **Calculate the distance for 11 seconds:** Using the speed, multiply by 11 seconds: $$\text{Distance} = 33 \times 11 = 363 \text{ feet}$$ 5. **Conclusion:** The elevator travels 363 feet in 11 seconds at the same speed.